Given, Polynomial
3x2 + 4x + 2k
Zero of the polynomial = – 2
As we have zero,
f(x) = 3x2 + 4x + 2k = 0
By putting x = – 2
f(– 2) = 3(– 2)2 + 4 (– 2) + 2k = 0
f(– 2) = 12 – 8 + 2k = 0
= 4 + 2k = 0
= 2k = – 4
k = – 4/2 = – 2
So we have the value of k = – 2