Question

If the product of zeros of the polynomial f(x) = ax³ – 6x² + 11x – 6 is 4, then a =

A. \(\frac{3}{2}\)

B. -\(\frac{3}{2}\)

C. \(\frac{2}{3}\)

D. - \(\frac{2}{3}\)

Answer 1

Given; Polynomial

= ax³ –6x² + 11x – 6

Let a,b,c be the zeroes of

f(x) = ax³ –6x² + 11x – 6

Product of the zeroes = – (constant term)/coefficient of x³

4 = – ( – 6)/a

4 = 6/a

4a = 6

a = 6/4

a = 3/2