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Solve the following systems of equations:

\(\frac{x}{7}\)\(\frac{y}{3}\) = 5

 \(\frac{x}{2}\)\(\frac{y}{9}\) = 6

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 \(\frac{x}{7}\)\(\frac{y}{3}\) = 5

⇒ 3x + 7y = 105

 \(\frac{x}{2}\)\(\frac{y}{9}\) = 6

⇒ 9x – 2y = 108

Multiplying eq1 by 3 and subtracting eq2 from it

⇒ 9x + 21y – 9x + 2y = 315 – 108

⇒ 23y = 207

⇒ y = 9

Thus,

9x – 18 = 108

⇒ x = 14

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