Method of cross multiplication
a1x + b1y + c1 = 0
a2x + b2y + c2 = 0
Given,
\(\frac{5}{x+y}\) - \(\frac{2}{x-y}\)= - 1
\(\frac{15}{x+y}\) + \(\frac{7}{x-y}\) = 10
Multiplying eq1 by 3 and subtracting from eq2
⇒ \(\frac{13}{x-y}\) = 13
⇒ x – y = 1 ------- (3)
Multiplying eq2 by 2 and eq1 by 7 and adding
⇒ 65/(x + y) = 13
⇒ x + y = 5 ---------- (4)
Thus,
⇒ x = 6/2 = 3 and y = 4/2 = 2