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Solve each of the following systems of equations by the method of cross-multiplication:

\(\frac{5}{x+y}\) - \(\frac{2}{x-y}\)= - 1

\(\frac{15}{x+y}\) + \(\frac{7}{x-y}\) = 10 where x ≠ 0 and y ≠ 0

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Method of cross multiplication

a1x + b1y + c1 = 0

a2x + b2y + c2 = 0

Given,

 \(\frac{5}{x+y}\) - \(\frac{2}{x-y}\)= - 1

\(\frac{15}{x+y}\) + \(\frac{7}{x-y}\) = 10

Multiplying eq1 by 3 and subtracting from eq2

⇒ \(\frac{13}{x-y}\) = 13

⇒ x – y = 1 ------- (3)

Multiplying eq2 by 2 and eq1 by 7 and adding

⇒ 65/(x + y) = 13

⇒ x + y = 5 ---------- (4)

Thus,

⇒ x = 6/2 = 3 and y = 4/2 = 2

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