Let the speed of train be ‘s’, scheduled time be ‘t’ and distance be ‘d’.
Speed = distance/time
Given,
Covered a certain distance at a uniform speed.
If the train could have been 10 km/hr. faster, it would have taken 2 hours less than the scheduled time.
And,
If the train were slower by 10 km/hr, it would have taken 3 hours more than the scheduled time.
⇒ d = st ------- (1)
d = (s + 10)(t – 2) ------ (2)
d = (s – 10)(t + 3) ------ (3)
Solving the above three equation we get,
d = 600 km,
s = 50 km/hr and
t = 12 hours