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A train covered a certain distance at a uniform speed. If the train could have been 10 km/hr. faster, it would have taken 2 hours less than the scheduled time. And, if the train were slower by 10 km/hr, it would have taken 3 hours more than the scheduled time. Find the distance covered by train.

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Let the speed of train be ‘s’, scheduled time be ‘t’ and distance be ‘d’.

Speed = distance/time

Given,

Covered a certain distance at a uniform speed.

If the train could have been 10 km/hr. faster, it would have taken 2 hours less than the scheduled time.

And,

If the train were slower by 10 km/hr, it would have taken 3 hours more than the scheduled time.

⇒ d = st ------- (1)

d = (s + 10)(t – 2) ------ (2)

d = (s – 10)(t + 3) ------ (3)

Solving the above three equation we get,

d = 600 km,

s = 50 km/hr and

t = 12 hours

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