Question

Solve the following quadratic equations by factorization:

\(abx^2+(b^2-ac)x-bc = 0\)

Answer 1

In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.

\(abx^2+(b^2-ac)x-bc = 0\)

⇒ abx² – acx + b²x – bc = 0 

⇒ ax(bx – c) + b(bx – c) = 0 

⇒ (ax + b)(bx – c) = 0 

⇒ x = -b/a, c/b