In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.
\(3x^2-2\sqrt{6}x+2=0\)
⇒ (√3x)2 – 2√6x + (√2)2 = 0
⇒ (√3x - √2)2 = 0
⇒ x \(\frac{\sqrt{2}}{\sqrt{3}},\)\(\frac{\sqrt{2}}{\sqrt{3}}\)
