To find: \(\int\limits_{0}^{2}
\)ex dx
Formula used:

where,

Here, f(x) = ex and a = 0

Now, by putting x = 0 in f(x) we get,
f(0) = e0 = 1
f(h)
= (e)h
= eh
Similarly, f(2h)
= e2h

This is G.P. (Geometric Progression) of n terms whose first term(a) is 1.
and common ratio(r) = \(\cfrac{e^h}1\) = eh
Sum of n terms of a G.P. is given by,

⇒ I = e2 - 1
Hence, the value of
\(\int\limits_{0}^{2}
\)ex dx = e2 - 1