I = \(\int\frac{ax^3+bx}{x^4+c^2}\)dx
As we can see that there is a term of x3 in numerator and derivative of x4 is also 4x3.
So there is a chance that we can make substitution for x4 + c2 and I can be reduced to a fundamental integration but there is also a x term present.
So it is better to break this integration.

To make the substitution,
I1 can be rewritten as,

∴ Let,
x4 + c2 = u
⇒ du = 4x3 dx
I1 is reduced to simple integration after substituting u and du as :

∵ We have derivative of x2 in numerator and term of x2 in denominator.
So we can apply method of substitution here also.

As denominator doesn’t have any square root term.
So one of the following two integrals will solve the problem.
