Given : sin2 A cot2A + cos2A tan2A =1
To prove : Above equality holds. Proof: Consider LHS, we know,
cot θ = \(\frac{cosθ}{sinθ}\) and tanθ = \(\frac{sinθ}{cosθ}\)
using these
sin2A cot2A + cos2A tan2A
= sin2A x \(\frac{cos^2A}{sin^2A}\) + cos2x \(\frac{sin^2A}{cos^2A}\)
= cos2A sin2A
= 1
Which is equal to RHS.
Hence Proved