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Prove the following trigonometric identities:

\(\frac{1+sin θ}{cos θ}+\frac{cos θ}{1+sin θ}\) =2sec θ

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\(\frac{1+sin θ}{cos θ}+\frac{cos θ}{1+sin θ}\)  = \(\frac{1+sin^2 θ+ 2sin θ+cos^2θ}{cos θ(1+sin θ)}\) 

= \(\frac{1+1+ 2sinθ}{cos θ(1+sin θ)}\) 

\(\frac{2+ 2sin θ}{cos θ(1+sin θ)}\)  

= \(\frac{2(1+sin θ)}{cos θ(1+sin θ)}\)  

=  \(\frac{2}{cosθ}\) 

= 2sec θ

Hence Proved

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