\(\frac{1+sin θ}{cos θ}+\frac{cos θ}{1+sin θ}\) = \(\frac{1+sin^2 θ+ 2sin θ+cos^2θ}{cos θ(1+sin θ)}\)
= \(\frac{1+1+ 2sinθ}{cos θ(1+sin θ)}\)
= \(\frac{2+ 2sin θ}{cos θ(1+sin θ)}\)
= \(\frac{2(1+sin θ)}{cos θ(1+sin θ)}\)
= \(\frac{2}{cosθ}\)
= 2sec θ
Hence Proved