Question

If a and b are unit vectors, then find the angle between a and b, given that √ 3a - b is a unit vector.

Answer 1

Given,  \(|\vec a|=|\vec b| = 1\) and  \(|\sqrt3\vec a+\vec b|=1\)

 By scalar product, \(|\vec a,\vec b|=|\vec a||\vec b|\) cos θ

By substituting the values, we get