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9 sec^2 A − 9 tan^2 A is equal to

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in Trigonometry by (30.5k points)
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9 sec2A − 9 tan2A is equal to 

A. 1 

B. 9 

C. 8 

D. 0

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1 Answer

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Best answer

To find: 9 sec2A – 9 tan2A 

Consider 9 sec2A – 9 tan2A = 9 (sec2A – tan2A) 

∵ 1 + tan2A = sec2A 

∴ 9 sec2A – 9 tan2A = 9 (sec2A – tan2A) 

= 9 (1 + tan2A – tan2A) = 9

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