Given two vectors \(4\hat i-\hat j + 3\hat k\) and \(-2\hat i+\hat j-2\hat k\)
Let \(\vec a=4\hat i-\hat j+3\hat k\) and \(\vec b=-2\hat i + \hat j-2\hat k\)
We need to find a unit vector perpendicular to \(\vec a\) and \(\vec b\).
Recall a vector that is perpendicular to two vectors


Here, we have (a1, a2, a3) = (4, –1, 3) and (b1, b2, b3) = (–2, 1, –2)

Let the unit vector in the direction of \(\vec a\times\vec b\) be \(\hat p\).
We know unit vector in the direction of a vector \(\vec a\) is given by \(\hat a=\cfrac{\vec a}{|\vec a|}\).

Recall the magnitude of the vector \(\text x\hat i+y\hat j+z\hat k\) is

Thus, the required unit vector that is perpendicular to both \(\vec a\) and \(\vec b\) is \(\cfrac13(-\hat i+2\hat j+2\hat k)\).