Question

A passenger arriving in a new town wishes to go from the station to hotel located 10km away on a straight road from the station. A dishonest cabman takes him along a circuitous path 23 km long and reaches the hotel in 28 minute, what is

1. The average speed of the taxi

2. The magnitude of average velocity? Are the two equal?

Answer 1

Magnitude of displacement = 10km

Total path length = 23km

Time taken = 28 min

Average speed = \(\frac{23km}{\frac{7}{15}h}\)

= 49.3 kmh^-1

Magnitude of average velocity