Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.2k views
in Law of Motion by (33.8k points)
closed by

1. Friction is the force which opposes the relative motion between two surfaces in contact with each other. What is a limiting static friction? State the laws related to this.

2. Show that the coefficient of friction is equal to the tan of the angle between the resultant and normal reactions.

3. For a body of mass 5kg on a plane at a limiting static friction of 30 degrees. What is the force of friction?

1 Answer

+1 vote
by (35.6k points)
selected by
 
Best answer

1. The maximum value of static friction is called limiting static friction.

  • The magnitude of the limiting friction is independent of the area of contact between the surfaces.
  • The limiting static friction is directly proportional to the normal reaction R.

ie f α R

fs = µsR.

2. Angle of friction is the angle whose tangent gives the coefficient of friction.

Consider a body placed on a surface. Let N be the normal reaction and limit is the limiting friction. Let ‘θ’ be the angle between Resultant vector and normal reaction. From the triangle OBC,

∴ tanθ = µ.

3. Tangent of the angle coefficient of friction.

µs = tanθ

µs = tan 30

µs = 1/√3

Friction F = µsmg

= 1/√3 × 5 × 10

F = \(\frac{50}{\sqrt 3}\)N.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...