Let I = ∫(x-2)√(2x2-6x+5)dx
Let us assume,

We know,
\(\frac{d}{dx}\)(xn) = nxn-1
And derivative of a constant is 0.
⇒ x – 2 = λ(2 × 2x2-1 – 6 – 0) + μ
⇒ x – 2 = λ(4x – 6) + μ
⇒ x – 2 = 4λx + μ – 6λ
Comparing the coefficient of x on both sides, we get
4λ = 1
⇒ λ = \(\frac{1}{4}\)
Comparing the constant on both sides, we get
μ – 6λ = –2

Substituting this value in I, we can write the integral as

Now,
Put 2x2 – 6x + 5 = t
⇒ (4x – 6)dx = dt
(Differentiating both sides)
Substituting this value in I1, we can write


Hence, we can write I2 as

