Question

For the equilibrium 

2SO₃(g) → 2SO₂(g) + O₂(g), K_c at 47 °C 3.25 × 10^-9 mol per litre.

What will be the value of K_p at this temperature (R = 8.314 J K^-1 mol^-1).

Answer 1

R = 8.314 J K^-1 mol^-1 ∆n = 3 – 2 = 1 

T = 47 °C = 273 + 47 = 320 K 

K_c = 3.25 × 10^-9

K_p = K_c (RT)^∆n 

= 3.25 × 10^-9 (8.314 × 320)¹ 

= 3.25 × 10^-9 × 8.314 × 320 

= 8.65 × 10^-12