Formula: -

Given: -
AB = position vector of B - position vector of A
= \(4\hat i-2\hat j-2\hat k\)
AC = position vector of C - position vector of A
= \(-2\hat i+4\hat j-2\hat k\)
AD = position vector of C - position vector of A
= \(-2\hat i-2\hat j+2\hat k\)
The four pint are coplanar if the vector are coplanar.
thus,

= 4(16 - 4) + 2( - 8 - 4) - 2( - 4 + 8) = 0
Hence proved.