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+1 vote
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The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0m. If the position moves with simple harmonic motion with an angular frequency of 200 rev/min, what is its maximum speed?

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Best answer

a = \(\frac{1}{2}\)m, ω = 200 rev/min

Umax = aω = \(\frac{1}{2}\) × 200m/min = 100 m/min.

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