Let required production of chairs and tables be x and y respectively.
Since, profits of each chair and table is Rs. 45 and Rs. 80 respectively. So, profits on x number of type A and y number of type B are 45x and 80y respectively.
Let Z denotes total output daily, so,
Z = 45x + 80y
Since, each chair and table requires 5 sq. ft and 80 sq. ft of wood respectively. So, x number of chair and y number of table require 5x and 80y sq. ft of wood respectively. But,
But 400 sq. ft of wood is available. So,
5x + 80y ≤ 400
x + 4y ≤ 80 {First Constraint}
Since, each chair and table requires 10 and 25 men - hours respectively. So, x number of chair and y number of table require 10x and 25y men - hours respectively. But, only 450 hours are available . So,
10x + 25y ≤ 450
2x + 5y ≤ 90 {Second Constraint}
Hence mathematical formulation of the given LPP is,
Max Z = 45x + 80y
Subject to constraints,
x + 4y ≤ 80
2x + 5y ≤ 90
x, y ≥ 0 [Since production of chairs and tables can not be less than zero]
Region x + 4y ≤ 80: line x + 4y = 80 meets the axes at A(80, 0), B(0, 20) respectively.
Region containing the origin represents x + 4y ≤ 80 as origin satisfies x + 4y ≤ 80
Region 2x + 5y ≤ 90: line 2x + 5y = 90 meets the axes at C(45, 0), D(0, 20) respectively.
Region containing the origin represents 2x + 5y ≤ 90
as origin satisfies 2x + 5y ≤ 90
Region x, y ≥ 0: it represents the first quadrant.
The corner points are O(0, 0), D(0, 18), C(45, 0).
The values of Z at these corner points are as follows:
The maximum value of Z is 2025 which is attained at C(45, 0).
Thus maximum profit of Rs 2025 is obtained when 45 units of chairs and no units of tables are produced.