LHS = \(1-\cfrac{sin^2\text x}{1+cot\,\text x}-\cfrac{cos^2\text x}{1+tan\,\text x}\)
We know that tan θ = \(\cfrac{sin\,\theta}{cos\,\theta}\) and cot θ = \(\cfrac{cos\,\theta}{sin\,\theta}\)

We know that a3 + b3 = (a + b) (a2 + b2- ab)

= 1 – (sin2x + cos2x) + sinx cosx
We know that sin2x + cos2x = 1.
= 1 – 1 + sinx cosx
= sinx cosx
= RHS
Hence proved.