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Prove the following identities

\(1-\cfrac{sin^2\text x}{1+cot\,\text x}-\cfrac{cos^2\text x}{1+tan\,\text x}\) = sin x cos x

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LHS \(1-\cfrac{sin^2\text x}{1+cot\,\text x}-\cfrac{cos^2\text x}{1+tan\,\text x}\)

We know that  tan θ = \(\cfrac{sin\,\theta}{cos\,\theta}\) and cot θ = \(\cfrac{cos\,\theta}{sin\,\theta}\)

We know that a3 + b3 = (a + b) (a2 + b2- ab)

= 1 – (sin2x + cos2x) + sinx cosx

We know that sin2x + cos2x = 1.

= 1 – 1 + sinx cosx

= sinx cosx

= RHS

Hence proved.

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