Take L.H.S,
4cosxcos(π/3+x)cos(π/3-x)

= 2 cos x {cos 120° + cos 2x}
= 2 cos x {cos (180° - 60°) + cos 2x}
{cos (180° - A) = - cos A}
= 2 cos x (cos 2x - cos 60°)
= 2 cos 2x cos x – 2 cos x cos 60°
= { cos(x + 2x) + cos(2x - x)} - \(\frac{2\,cos\,x}{2}\)
= cos 3x + cos x – cos x
= cos 3x
= R.H.S.
Hence Proved.