Question

Write the maximum and minimum values of 3 cos x + 4 sin x + 5.

Answer 1

the maximum value of (a cosx + bsinx) = \(\sqrt{a^2+b^2}\)

So maximum value = \(\sqrt{9+16}\)

= 5 

the minimum value of (a cosx + b sinx) = - \(\sqrt{a^2+b^2}\)

minimum value = - 5