Question

1. Draw the logic circuit for the Boolean expression:

\((A+\overline {BC})+\overline {AB}\)

2. Using algebraic method prove that

\(\bar Y⋅ \bar Z + \bar Y ⋅ Z + Y ⋅ Z + Y = 1\)

Answer 1

1. 

OR

2. L.H.S. =  \( \bar Y ⋅ \bar Z + \bar Y ⋅ Z + Y Z + Y\)

= \(\bar y ⋅ (\bar z + z) + y ⋅ (z + 1)\)

 = \(\bar y. 1 + \bar y ⋅ 1 = y ⋅ y = 1\)