Given,
AP is 24, 21, 18, 15, ……
First term of AP is a = 24.
Common difference of AP is d = a2 − a1
= 21 − 24 = −3.
Since,
First term is 24 which is multiple of 3 and common difference is – 3.
Therefore,
All terms of AP are multiple of 3.
∴ First negative term of given AP is – 3.
Let nth term of AP is – 3.
∴ a + (n − 1)d = −3
(∵ n th term of AP is given by an = a + (n − 1)d)
⇒ 24 + (n − 1) × −3 = −3
(∵ a = 24 & d = −3)
⇒ −3(n − 1)
= −3 − 24
= −27
⇒ n −1 = \(\frac{-27}{-3}\) = 9
⇒ n = 1 + 9 = 10.
Hence,
10th term of given AP is the first negative term.