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In quadrilateral ACBD, AC= AD and AB bisects L A . Show that triangle ABC is congruent to triangle ADB. What can you say about BC and BD?

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`/_CAB=/_DAB`
`/_ABC and /_ABD`
`AC=AD`
`/_CAB=/_OAB`
AB side is common
So, by SAS rule(side-angle-side)
`/_ABC cong /_ABD`
`/_ABC cong /_ABD`
`/_CAB=/_DAB`
if two triangle are congrent.
Side corresponding to same angle. They are equal
`/_CAB=/_DAB`
therefore BC=BD.

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