Given,
The word MATHEMATICS.
It has 11 letters of which the letters M, A, and T are repeating and all letters are repeated twice.
Since we know,
Permutation of n objects taking r at a time is nPr,and permutation of n objects taking all at a time is n!
And,
We also know,
Permutation of n objects taking all at a time having p objects of same type, q objects of another type, r objects of another type is \(\frac{n!}{p!\times q!\times r!}\).
i.e,
The number of repeated objects of same type are in denominator multiplication with factorial.
Total number of permutations of 11 objects with 3 objects repeating twice = \(\frac{11!}{2!\times 2!\times 2!}\)
= 4989600
To find the number of words starting with the letter C :
This will be equal to permutation of 10 letters (excluded the letter C) where 3 letters (M, A, and T) are repeated twice = \(\frac{10!}{2!\times 2!\times 2!}\)
Total number of permutations of 11 objects with 3 objects repeating twice = \(\frac{11!}{2!\times 2!\times 2!}\)
= 4989600
To find the number of words starting with the letter C: This will be equal to permutation of 10 letters (excluded the letter C) where 3 letters (M, A, and T) are repeated twice = \(\frac{10!}{2!\times 2!\times 2!}\)
= 453600
To find the number of words starting with the letter T :
This will be equal to permutation of 10 letters (excluded the letter T) where 2 letters (M, A) are repeated twice,
Which will be equals to :
⇒ \(\frac{10!}{2!\times 2!}\)
= 907200
Hence,
A total number of words permuting the letters of word MATHEMATICS is 4989600.
A total number of words starting with the letter C is 453600.
A total number of words starting with the letter T equals 907200.