Major axis lie on the y-axis so the standard equation of the ellipse is of the form
\(\frac{x^2}{a^2}+ \frac{y^2}{b^2} = 1\)
Since the ellipse passes through (3, 2)
\(\frac{9}{a^2} + \frac{4}{b^2} = 1\) .........(1)
Since the ellipse passes through (1, 6)
\(\frac{1}{a^2} + \frac{36}{b^2} = 1\) ......... (2)
Solving (1) and (2), we have Since the ellipse passes through (3, 2)
a2 = 40; b2 = 10
Thus the equation of the ellipse is
\(\frac{x^2}{40}+ \frac{y^2}{10}\)= 1
