(i) Frequency of body, (n) = 250 Hz.
Distance, (d) = 175 m.
Speed (velocity) of sound (V) `= 350 ms^(-1)`.
`therefore` Time taken by the sound to travel 175 m in air `= ("distance")/("speed") = (175 m)/(350 ms^(-1)) = 1/2 s.`
(ii) When it is vibrated in water, the number of vibrations completed in 1 second (i.e., frequency) is the same
`therefore` n = 250 Hz.
Distance, (d) = 175 m
Speed of sound in water `(v) = 1400 ms^(-1)`.
`therefore` Time taken by sound to travel 175 m in water (t).
`= (175 m)/(1400 ms^(-1)) = 1//8 s`
`therefore` Time difference `= (1/2 - 1/8)s`
`= (1/2 - 1/8)s = (4/8 - 1/8)s = 3/8s`.