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+1 vote
15.3k views
in Introduction to Three Dimensional Geometry by (15.3k points)

Find the ratio in which the line joining the points (1, 2, 3) and (-3, 4, -5) is divided by the xy-plane.

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1 Answer

+2 votes
by (15.9k points)

Let the line joining the points A(1, 2, 3) and B(-3, 4, -5) is divided by the xy-plane in the ratio k:1. 

Then the coordinate

x = \(\frac{-3k + 1}{k+1}\); y = \(\frac{4k + 2}{k+1}\); z = \(\frac{-5k+3}{k+1}\)

Since the point lies on xy-axis, we have;

\(z = 0 \Rightarrow \frac{-5k+3}{k+1}\) = 0 \(\Rightarrow \) -5k + 3 = 0 \(\Rightarrow\) k = \(\frac{3}{5}\)

Thus the required ratio is \(\frac{3}{5}\); ie, 3:5.

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