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Divide 184 into two parts such that one-third of one part may exceed one-seventh of the other part by 8.

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Divide 184 into two parts such that one-third of one part may exceed one-seventh of the other part by 8.
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Let the two parts are `x` and `184-x`.
then, `x/3 = 1/7(184-x)+8`
`=>7x = 3((184-x)+56)`
`=>7x = 552-3x+168`
`=>10x = 720`
`=> x = 72`
So, other part = `184 - 72 = 112`.
So, two parts are `72` and `112`.
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