\(\lim\limits_{x \to 0^-}\) f(x) = \(\lim\limits_{x \to 0}\)(2x + 3) = 3
\(\lim\limits_{x \to {0^+}}\) f(x) = \(\lim\limits_{x \to 0}\)3(x +1) = 3
Therefore; \(\lim\limits_{x \to 0}\) f(x) = 3
\(\lim\limits_{x \to 1}\) f(x) = \(\lim\limits_{x \to 1}\) 3(x+1) = 3 x 2 = 6