Sarthaks Test
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ABCD is a parallelogram in which BC is produced to E such that CE = BC. AE intersects CD at F. 

(i) Prove that ar (∆ADF) = ar (∆ECF) 

(ii) If the area of ∆DFB = 3 cm2 , find the area of ||gm ABCD.

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In triangles ADF and ECF, we have

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