When x = 1, y = 7 ∈ N, so (1, 7) ∈ R. Again for,
x = 2 . y = 2 + 6/2 = 2 + 3 = 5 ∈ N, so (2, 5) ∈ R.
Again for
x = 3, y = 3 + 6/3 = 3 + 2 = 5 ∈ N, (3, 5) ∈ R. Similarly for x = 4
y = 4 + 6/4 ∉ N and for x = 5 , y = 5 + 6/5 ∉ N
Thus R = {(1, 7), (2, 5), (3, 5)}, where Domain of R = {1, 2, 3}
Range of R = {7, 5}