Question

The time in seconds taken for 20 oscillations noted down in an simple pendulum experiment are `38.6, 40.0, 41.5, 42.8 and 39.4`, the time period of the given simple pendulum is ____ s
A. `2.5`
B. `2.2`
C. `2.0`
D. `10.1`

Answer 1

Correct Answer - C
`T = (38.6 + 40 + 41.5 + 42.8 + 39.4)/((5)/(20))`
`= 2.023s ~~ 2s`