Question

A and B throw a pair of dice. If A throws 9, find B’s chance of throwing a higher number.

Answer 1

Given: pair of dice

Formula: P(E) = \(\frac{favorable\ outcomes}{total\ possible\ outcomes}\) 

A and B throw a pair of dice 

we have to find the probability that B throw’s a higher number 

total possible outcomes are ⁶C₁ ⁶C₁

therefore n(S) = 6² = 36 

let E be the event that A throws 9, and B throws greater than 9 

E= {(4,6) (5,5) (5,6) (6,4) (6,5) (6,6)} 

n(E)= 6 

probability of occurrence of the event is

P(E) = \(\frac{n(E)}{n(S)}\)

P(E) = \(\frac{6}{36} = \frac{1}{6}\)