Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
187 views
in Statistics by (88.7k points)
closed by
Find mean deviation for the following data about median:
`{:("Class Interval",5-9,10-14,15-19,20-24,25-29),(f,5,9,12,8,6):}`

1 Answer

0 votes
by (97.2k points)
selected by
 
Best answer
image
`(N)/(2) = (40)/(2) = 20, L = 14.5, F = 14, f = 12, C = 5`
`"Median" = L + ((N/2)-f)/(f) xx C`
`=14.5 + (20-14)/(12) xx 5`
`=14.5 + 2.5 = 17`
`therefore "MD" = (Sum f|x - bar(x)|)/(N) "or" (sum fD)/(N)`
`= (195)/(40) = 4.875`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...