1. Firm: A
Number of wages earners (n1) = 586
Number of wages earners (\(\bar x_1\)) = 5253
Total monthly wages = 5253 × 586 = 3078258
Firm: B
Number of wages earners (n1) = 648
Number of wages earners (\(\bar x\)) = 5253
Total monthly wages = 5253 × 648 = 3403944
2. Since both the firms have same mean of monthly wages, so the firm with greater variance will have more variability in individual wages. Thus firm B will have more variability in individual wages.