Question

If `(a+b)/(xa+yb) = (b+c)/(xy+yc) = (c+a)/(xc+ya)" where " x + y ne 0`
and ` a + b + c ne 0`, then each of these ratios is equal to
A. 1
B. `1/(x+y)`
C. ` 2/(x+y)`
D. ` 2 /(a+b)`

Answer 1

Correct Answer - C
(i) Bach ratio = `("Sum of all antecedents")/("Sum of all the consequents")`.
(ii) Bach fraction is equal to the ratio of sum of the numerators and the sum of the denominators of all the equivalent fractions.