Let T denotes the event that person travels by train and A denotes that event that person travels by plane
Given, P(T) = \(\frac{3}{5}\) and P(A) = \(\frac{1}{4}\)
We need to find the probability that person travels by plane or train i.e. P(T or A) = P(T∪A)
Note: By definition of P(A or B) under axiomatic approach(also called addition theorem) we know that:
P(A∪B) = P(A) + P(B) – P(A ∩ B)
∴ P(T∪A) = P(T) + P(A) – P(A ∩ T)
∵ A person can never travel with both plane and train simultaneously.
∴ P(A∩T) = 0
Hence,
P(T∪A) = P(T) + P(A) = \(\frac{3}{5}\) + \(\frac{1}{4}\) = \(\frac{17}{20}\)