Draw perpendiculars OA and OB on RS and SM respectively.
OR = OS = OM = 5 m. (Radii of the circle)
In ΔOAR,
OA2 + AR2 = OR2
OA2 + (3 m)2 = (5 m)2
OA2 = (25 − 9) m2 = 16 m2
OA = 4 m
ORSM will be a kite (OR = OM and RS = SM). We know that the diagonals of a kite are perpendicular and the diagonal common to both the isosceles triangles is bisected by another diagonal.
∠∠RCS will be of 90° and RC = CM
Therefore, the distance between Reshma and Mandip is 9.6 m.