Question

मान ज्ञात कीजिए ।
`(i) 64^(1//2)` `(ii) 32^(1//5)` `(iii) 125^(1//3)`

Answer 1

`(i) 64^(1//2)=(8xx8)^(1//2)=(8^(2))^(1//2)=8^(2xx(1)/(2))=8^(1)=8`
`(ii) 32^(1//5)=(2xx2xx2x2xx2)^(1//5)=(2^(5))^(1//5)=2^(5xx(1)/(5))=2^(1)=2`
`(iii) 125^(1//3)=(5xx5xx5)^(1//3)=5^(3xx(1)/(3))=5^(1)=5`