प्रश्ननुसार , `(9^(n)xx3^(2)xx(3^(-n//2))^(-2)-(27)^(n))/(3^(3m)xx2^(3))=(1)/(27)`
`implies((3^(2))^(n)xx3^(2)xx3^(-n//2xx-2)-(3^(3))^(n))/(3^(3m)xx2^(3))=(1)/(27)`
`implies(3^(2n)xx3^(2)xx3^(n)-3^(3n))/(3^(3m)xx2^(3))=(1)/(27)implies(3^(2n+2+n)-3^(3n))/(3^(3m)xx2^(3))=(1)/(27)`
`implies(3^(3n+2)-3^(3n))/(3^(3m)xx2^(3))=(1)/(27)implies(3^(3n)(3^(2)-1))/(3^(3m)xx2^(3))=(1)/(27)`
`implies(3^(3n)*8)/(3^(3m)*8)=(1)/(27)implies3^(3n-3m)=(1)/(3^(3))=3^(-3)`
`implies 3n-3m=-3`
यदि `n-m=1` , अर्थात `m-n=1`
