Given, Numbers of observations are given in two groups.
To Find: Calculate the Mean Deviation from their Median.
Formula Used: Mean Deviation = \(\frac{\Sigma d_i}{n}\)
For Group 1: Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the Income of Group 1 in Ascending order, we get 4000, 4200, 4400, 4600, 4800
Therefore, The Median = 4400
Deviation |d| = |x-Median|
Now, The Mean Deviation is
X1 |
|di|=|xi-4400| |
4000 |
400 |
4200 |
200 |
4400 |
0 |
4600 |
200 |
4800 |
400 |
Total |
1200 |
Mean Deviation = \(\frac{\Sigma d_i}{n}\)
Mean Deviation Of Group 1 = \(\frac{1200}{5}\) = 240
For Group 2: Since, Median is the middle number of all the observation,
So, To Find the Median, Arrange the Income of Group 2 in Ascending order, we get 3800,4000,4200,4400,4600,4800,5800
Therefore, The Median = 4400
Deviation |d| = |x-Median|
Now, The Mean Deviation is
X1 |
|di|=|xi-4400| |
3800 |
600 |
4000 |
400 |
4200 |
200 |
4400 |
0 |
4800 |
200 |
5800 |
1400 |
Total |
3200 |
Mean Deviation = \(\frac{\Sigma d_i}{n}\)
Mean Deviation Of Group 2 = \(\frac{3200}{7}\) = 457.14
Hence, The Mean Deviation of Group 1 is 240 and Group 2 is 457.14