
Using homogenization
x2 + 2y2 = 2(1)2
⇒x2 + 2y2 = 2(x + y)2
⇒x2 + 2y2 = 2x2 + 2y2 + 4xy
⇒x2 + 4xy = 0
for ax2 + 2hxy + by2 = 0, obtuse angle between lines θ is
tan θ = ±(2√(h2–ab))/(a+b)
⇒tan θ = ±4
⇒tan θ = –4
cot θ = -1/4
θ = cot–1(–1/4)
θ = π – cot–1 (1/4)
θ = π – (π/2– tan–1(1/4) )
θ = π/2 + tan-1(1/4)