Question

The length of the parallel sides of a trapezium are 19 cm and 13 cm and its area is 128 cm². The distance between the parallel sides is 

A. 9 cm 

B. 7 cm 

C. 8 cm 

D. 12.5 cm

Answer 1

Given 

Length of parallel sides is 19 cm and 13 cm 

Area of trapezium= 128 cm² Let Height (h) = y cm 

We know that area of trapezium is \(\frac{1}{2}\)× (sum of parallel sides) × height

Therefore Area of trapezium is \(\frac{1}{2}\)× (19 +13) × y = 128 cm².

∴ \(\frac{1}{2}\)× (19 +13) × y =128

⇒ \(\frac{1}{2}\)× (32) × y =128

⇒ 16 × y = 128

⇒ y = \(\frac{128}{16}\) = 8 cm

∴ Distance between the parallel lines is 8 cm.