Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
79 views
in Chemistry by (43.5k points)
closed by
Calculate the number of molecules of sulphur `(S_(8))` present in 16 g of solid sulphur.

1 Answer

0 votes
by (40.8k points)
selected by
 
Best answer
Correct Answer - `3.76 xx 10^(22)` molecules
1 mole of solid sulphur (S8) = 8 × 32g = 256g i.e., 256g of solid sulphur contains = 6.022 × 1023 molecules
Then, 16g of solid sulpur contains `=6.022xx10^(23)//256=16` molecules
`= 3.76 × 10^(22)` molecules

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...