A polygon of 16 sides
We have given that polygon has 16 vertices and each side and diagonal can be formed by joining two vertices of a polygon,
Let us assume the no. of diagonals of the polygon are N,
⇒ N = (no. of lines formed on joining any two vertices) – (no. of sides of the polygon)
⇒ N = 16C2 – 16
We know that,
nCr = \(\frac{n!}{(n-r)!r!}\)
And also,
n! = (n)(n – 1)......2.1

⇒ N = 120 – 16
⇒ N = 104
∴ The total no. of diagonals formed are 104.