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A sample of water under study was found to boil at `102^(@)C` at normal temperature and pressure. Is the water pure ? Will this water freeze at `0^(@)C` ?

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Under normal temperature and pressure, the boiling point temperature of pure water is `100^(@)C`. The boiling point of `102^(@)C` means that the given sample is impure and has non-volatile impurities present. This impure sample will have freezing point temperature below `0^(@)C`. Please remember that the presence of impurities raises the boiling point temperature of a liquid and lowers its freezing point.

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